Python challenge_11

Tic tac toe input

level of challenge 4/10

Here's the backstory for this challenge:

imagine you're writing a tic-tac-toe game, where the board looks like this:

1:  X | O | X
        -----------
    2:    |   |  
        -----------
    3:  O |   |
        A   B  C

The board is represented as a 2D list:

board = [
    ["X", "O", "X"],
    [" ", " ", " "],
    ["O", " ", " "],
]

Imagine if your user enters "C1" and you need to see if there's an X or O in that cell on the board.

To do so, you need to translate from the string "C1" to row 0 and column 2

so that you can check board[row][column].

Your task is to write a function that can translate from strings of length 2 to a tuple (row, column).

Name your function get_row_col.

it should take a single parameter which is a string of length 2 consisting of an uppercase letter and a digit.

For example:

Calling get_row_col("A3") should return the tuple (2, 0).

Because A3 corresponds to the row at index 2 and column at index 0 in the board.

Hint:

First, use indexing to extract the number and letter.

Use int() to cast the number from a string to an int.

You can use a dictionary to translate the letter into a number.

Return the result as a tuple: (row, column).

My Solution

board = [
    ["X", "O", "X"], # 1
    [" ", " ", " "], # 2
    ["O", " ", " "], # 3
]   # A    B    C

def get_row_col(tic_tac):
    tic = tic_tac.upper()
    col = tic[0]
    row = int(tic[1]) - 1

    board_keys = {"A": 0, "B": 1, "C": 2}

    for key in board_keys:
        if key == col:
            column = board_keys[key]
            return (row, column)

print(get_row_col("c1"))

Another solution

def get_row_col(choice):
    translate = {"A": 0, "B": 1, "C": 2}
    letter = choice[0]
    number = choice[1]
    row = int(number) - 1
    column = translate[letter]
    return (row, column)