Working With Regex Expressions In Python

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This is Day 14 of the #100DaysOfPython challenge

This post will use the regular expressions module from the standard library to ... .

Prerequisites

Familiarity with Pipenv. See here for my post on Pipenv.
Familiarity with JupyterLab. See here for my post on JupyterLab.
Familiarity with Regular Expressions

Getting started

Let's create the hello-python-regex directory and install Pillow.

# Make the `hello-python-regex` directory
$ mkdir hello-python-regex
$ cd hello-python-regex
# Create a folder to place your icons
$ mkdir icons

# Init the virtual environment
$ pipenv --three
$ pipenv install --dev jupyterlab

At this stage, we can start up the notebook server.

# Startup the notebook server
$ pipenv run jupyter-lab
# ... Server is now running on http://localhost:8888/lab

The server will now be up and running.

Creating the notebook

Once on http://localhost:8888/lab, select to create a new Python 3 notebook from the launcher.

Ensure that this notebook is saved in hello-python-regex/docs/regex.ipynb.

We will explore the following in each cell of the notebook:

Importing the Regex module.
A basic usage of the Regex module.
String replacement with the Regex module.

Importing the module

This imports the regex module from the standard library.

import re

m = re.search("Hello, (.+)", "Hello, world!")
m.group(1)
# 'world!'

Basic usage of the module

There are a number of useful module methods that we can use that we will demonstrate:

Searching strings.
Matching strings.
Usage without compile.
Splitting a string into a list.
Replacing matches.

Searching strings

Scan through string looking for the first location where this regular expression produces a match, and return a corresponding match object. Return None if no position in the string matches the pattern; note that this is different from finding a zero-length match at some point in the string.

import re

pattern = re.compile("ello, (.+)")
m = pattern.search("Hello, world!")
m.group(1)
print(m) # <re.Match object; span=(0, 13), match='Hello, world!'>
print(m.group(1)) # world!

n = pattern.search("Hello, world!", 0)
print(n) # <re.Match object; span=(0, 13), match='Hello, world!'>
print(n.group(1)) # world!

Matching strings

If zero or more characters at the beginning of string match this regular expression, return a corresponding match object. Return None if the string does not match the pattern; note that this is different from a zero-length match.

pattern = re.compile("ello, (.+)")
m = pattern.match("Hello, world!")
# No match as "e" is the 2nd character the "Hello, world!".
print(m) # None

pattern = re.compile("Hello, (.+)")
# Does match
n = pattern.match("Hello, world!")
print(n) # <re.Match object; span=(0, 13), match='Hello, world!'>

Usage without compile

When you use re.match and re.search as a static method, you can pass the Regex as the first argument:

m = re.match("Hello, (.+)", "Hello, world!")
print(m) # <re.Match object; span=(0, 13), match='Hello, world!'>

n = re.match("Hello, (.+)", "Hello, world!")
print(n) # <re.Match object; span=(0, 13), match='Hello, world!'>

Splitting a string into a list

m = re.split(",", "Hello, world!")

print(m) # ['Hello', ' world!']

n = re.split("\s", "Hello beautiful world!")

print(n) # ['Hello', 'beautiful', 'world!']

Replacing matches

We can make use of the search and sub methods to replace matches.

# Simple example
target = "Photo credit by [@thomas](https://site.com/@thomas)"
m = re.search(r"Photo credit by \[@(.+)\]\(https://site.com/@(.+)\)", target)
res = re.sub(m.group(1), "dennis", target)
print(res) # Photo credit by [@dennis](https://site.com/@dennis)

# By iterating for multiple matches
target = "Photo credit by [@thomas](https://site.com/@user)"
m = re.search(r"Photo credit by \[@(.+)\]\(https://site.com/@(.+)\)", target)
res = target

for idx, val in enumerate(m.groups()):
        res = re.sub(val, "dennis", res)

print(res) # Photo credit by [@dennis](https://site.com/@dennis)

For a more specific replacement (particularly in a large set of text), we can be more explicit with the string to replace:

target = """
Other words thomas and user we don't want to replace.
Photo credit by [@thomas](https://site.com/@user)
"""
new_name = "dennis"

pattern = re.compile(r"Photo credit by \[@(.+)\]\(https://site.com/@(.+)\)")
res = pattern.sub(f"Photo credit by [@{new_name}](https://site.com/@{new_name})", target)
# Other words thomas and user we don't want to replace.
# Photo credit by [@dennis](https://site.com/@dennis)