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Top 20 JavaScript tips and tricks to increase your Speed and Efficiency
In our daily tasks, we get to write functions such as sorting, searching, finding unique values, passing parameters, swapping values etc, so here I present my list of shorthand techniques to write all of them as a Pro!✌🏻
JavaScript is truly an awesome language💛 to learn and work with. And there can be more than one approach to reach to the same solution for given problem. In this article, we will discuss only the quickest ones.🚀
These approaches will definitely help you in:
- Reducing the number of LOC(lines of code),
- Coding Competitions,
- Hackathons or
- Other time bound tasks.⏱
Most of these JavaScript Hacks uses techniques from ECMAScript6(ES2015) onwards, though the latest version is ECMAScript11(ES2020).
Note: All below tricks have been tested on the Console of Google Chrome.
We can initialize array of particular size with default values like ""
, null
or 0
. You might have used these for the 1-D array but how about initializing 2-D array/matrix?
const array = Array(5).fill('');
// Output
(5)Â ["", "", "", "", ""]
const matrix = Array(5).fill(0).map(()=>Array(5).fill(0));
// Output
(5) [Array(5), Array(5), Array(5), Array(5), Array(5)]
0: (5) [0, 0, 0, 0, 0]
1: (5) [0, 0, 0, 0, 0]
2: (5) [0, 0, 0, 0, 0]
3: (5) [0, 0, 0, 0, 0]
4: (5) [0, 0, 0, 0, 0]
length: 5
We should make use of reduce
method to quickly find basic maths operations.
const array = [5,4,7,8,9,2];
- Sum
array.reduce((a,b) => a+b);
// Output: 35
- Max
array.reduce((a,b) => a>b?a:b);
// Output: 9
- Min
array.reduce((a,b) => a<b?a:b);
// Output: 2
We have inbuilt methods sort()
and reverse()
for sorting strings but How about numbers or array of objects?
Let's check out sorting hacks for Numbers and Objects in Increasing and Decreasing order as well.
- Sort String Array
const stringArr = ["Joe", "Kapil", "Steve", "Musk"]
stringArr.sort();
// Output
(4)Â ["Joe", "Kapil", "Musk", "Steve"]
stringArr.reverse();
// Output
(4)Â ["Steve", "Musk", "Kapil", "Joe"]
- Sort Number Array
const array = [40, 100, 1, 5, 25, 10];
array.sort((a,b) => a-b);
// Output
(6)Â [1, 5, 10, 25, 40, 100]
array.sort((a,b) => b-a);
// Output
(6)Â [100, 40, 25, 10, 5, 1]
- Sort Array of Objects
const objectArr = [
{ first_name: 'Lazslo', last_name: 'Jamf' },
{ first_name: 'Pig', last_name: 'Bodine' },
{ first_name: 'Pirate', last_name: 'Prentice' }
];
objectArr.sort((a, b) => a.last_name.localeCompare(b.last_name));
// Output
(3) [{…}, {…}, {…}]
0: {first_name: "Pig", last_name: "Bodine"}
1: {first_name: "Lazslo", last_name: "Jamf"}
2: {first_name: "Pirate", last_name: "Prentice"}
length: 3
Falsy values like 0
, undefined
, null
, false
, ""
, ''
can be omitted easily through below trick
const array = [3, 0, 6, 7, '', false];
array.filter(Boolean);
// Output
(3)Â [3, 6, 7]
If you want to reduce nested if..else or switch cases, you can simply play with basic of logical operators AND/OR
.
function doSomething(arg1){
arg1 = arg1 || 10;
// set arg1 to 10 as a default if it’s not already set
return arg1;
}
let foo = 10;
foo === 10 && doSomething();
// is the same thing as if (foo == 10) then doSomething();
// Output: 10
foo === 5 || doSomething();
// is the same thing as if (foo != 5) then doSomething();
// Output: 10
You might have used indexOf()
with for loop which return first found index or newer one includes()
which returns boolean true/false from the array to find out/remove duplicates. Here's we have 2 quicker approaches.
const array = [5,4,7,8,9,2,7,5];
array.filter((item,idx,arr) => arr.indexOf(item) === idx);
// or
const nonUnique = [...new Set(array)];
// Output: [5, 4, 7, 8, 9, 2]
Most of the time, the requirement to solve problem by creating counter object or map which tracks variables as keys with their frequency/occurrences as values.
let string = 'kapilalipak';
const table={};
for(let char of string) {
table[char]=table[char]+1 || 1;
}
// Output
{k: 2, a: 3, p: 2, i: 2, l: 2}
and
const countMap = new Map();
for (let i = 0; i < string.length; i++) {
if (countMap.has(string[i])) {
countMap.set(string[i], countMap.get(string[i]) + 1);
} else {
countMap.set(string[i], 1);
}
}
// Output
Map(5)Â {"k" => 2, "a" => 3, "p" => 2, "i" => 2, "l" => 2}
You can avoid nested conditional if..elseif..elseif with ternary operators.
function Fever(temp) {
return temp > 97 ? 'Visit Doctor!'
: temp < 97 ? 'Go Out and Play!!'
: temp === 97 ? 'Take Some Rest!';
}
// Output
Fever(97): "Take Some Rest!"
Fever(100): "Visit Doctor!"
-
for
andfor..in
gets you index by default, but you can use arr[index]. -
for..in
accepts non numeric as well so avoid it. -
forEach
,for...of
gets you element directly. -
forEach
can get you index also butfor...of
can't. -
for
andfor...of
considers holes in array but other 2 do not.
Often we need to merge multiple objects in our daily tasks.
const user = {
name: 'Kapil Raghuwanshi',
gender: 'Male'
};
const college = {
primary: 'Mani Primary School',
secondary: 'Lass Secondary School'
};
const skills = {
programming: 'Extreme',
swimming: 'Average',
sleeping: 'Pro'
};
const summary = {...user, ...college, ...skills};
// Output
gender: "Male"
name: "Kapil Raghuwanshi"
primary: "Mani Primary School"
programming: "Extreme"
secondary: "Lass Secondary School"
sleeping: "Pro"
swimming: "Average"
An arrow function expression is a compact alternative to a traditional function expression, but is limited and can't be used in all situations. Since they have lexical scope (parental scope) and does not have their own this
and arguments
hence they refer to the environment in which they are defined.
const person = {
name: 'Kapil',
sayName() {
return this.name;
}
}
person.sayName();
// Output
"Kapil"
But
const person = {
name: 'Kapil',
sayName : () => {
return this.name;
}
}
person.sayName();
// Output
""
The optional chaining ?. stops the evaluation if the value before ?. is undefined or null and returns undefined.
const user = {
employee: {
name: "Kapil"
}
};
user.employee?.name;
// Output: "Kapil"
user.employ?.name;
// Output: undefined
user.employ.name
// Output: VM21616:1 Uncaught TypeError: Cannot read property 'name' of undefined
Making use of inbuilt Math.random()
method.
const list = [1, 2, 3, 4, 5, 6, 7, 8, 9];
list.sort(() => {
return Math.random() - 0.5;
});
// Output
(9)Â [2, 5, 1, 6, 9, 8, 4, 3, 7]
// Call it again
(9)Â [4, 1, 7, 5, 3, 8, 2, 9, 6]
The nullish coalescing operator (??) is a logical operator that returns its right-hand side operand when its left-hand side operand is null or undefined, and otherwise returns its left-hand side operand.
const foo = null ?? 'my school';
// Output: "my school"
const baz = 0 ?? 42;
// Output: 0
Those mysterious 3 dots ...
can rest or spread!🤓
function myFun(a, b, ...manyMoreArgs) {
return arguments.length;
}
myFun("one", "two", "three", "four", "five", "six");
// Output: 6
and
const parts = ['shoulders', 'knees'];
const lyrics = ['head', ...parts, 'and', 'toes'];
lyrics;
// Output:
(5)Â ["head", "shoulders", "knees", "and", "toes"]
const search = (arr, low=0,high=arr.length-1) => {
return high;
}
search([1,2,3,4,5]);
// Output: 4
We can use some in-built methods like .toPrecision()
or .toFixed()
to achieve much of helping functionalities while solving problems.
const num = 10;
num.toString(2);
// Output: "1010"
num.toString(16);
// Output: "a"
num.toString(8);
// Output: "12"
let a = 5;
let b = 8;
[a,b] = [b,a]
[a,b]
// Output
(2)Â [8, 5]
Well, this is not a shorthand trick overall but it will give you clear idea to play with strings.
function checkPalindrome(str) {
return str == str.split('').reverse().join('');
}
checkPalindrome('naman');
// Output: true
Using Object.entries()
,Object.keys()
and Object.values()
const obj = { a: 1, b: 2, c: 3 };
Object.entries(obj);
// Output
(3) [Array(2), Array(2), Array(2)]
0: (2) ["a", 1]
1: (2) ["b", 2]
2: (2) ["c", 3]
length: 3
Object.keys(obj);
(3)Â ["a", "b", "c"]
Object.values(obj);
(3)Â [1, 2, 3]
So that's it guys for now! 🤗
If you know few more hacks like above, let's collaborate through GitHub Repository, so that we can all learn them together.
If you really learned something new with this article or it really made your dev work faster than before, like it, save it and share it with your colleagues.
I have been writing tech blogs for quite a time now, and have mostly published through my Medium account, this is my first tech article/tutorial in Dev.to. Hope you guys will shower love to it!🤩
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