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2 ways to use static with functions in C++
I've been doing a code review lately and I saw the following piece of code (I anonymized it) in a .cpp
file:
static bool isWineColour(const std::string& iWineCoulour) {
static const std::array<std::string, 3> wineCoulours{ "white", "red", "rose" };
return std::find(wineCoulours.begin(), wineCoulours.end(), iWineCoulour)
!= wineCoulours.end();
}
I read the code and it made sense, but I didn't really get it. WTF. Do we return a static bool
? What? I've never seen anything like that in a cpp
file and it wouldn't make sense, would it?
But it said static bool
and we are not in the header. There is no isWineColour()
function declared in the header at all.
At this point, I understood that either there is something very wrong here or I am missing the point. Given that the code compiled, the tests succeeded and SonarQube didn't report any code smells, it was pretty clear that I was missing the point.
Just to make it clear, before I reveal the big secret (no, there is no big secret...) there is no such thing as a static
return type. When the keyword static
appears in front of the return type, it might be mean one of these two possibilities:
- a member function is
static
- a free-function cannot be accessed by any other translation unit
So the difference between the two usages is that in one case, we use static
with a member function in the other we use it with a free-function.
Let's get into details.
Okay, probably this one you already knew. If you make a class member function static, it means that you can call it without going through an instance of the class.
#include <iostream>
#include <type_traits>
class A {
public:
static void Foo() {
std::cout << "A::foo is called\n";
}
};
int main() {
A a;
a.Foo();
A::Foo();
}
/*
A::foo is called
A::foo is called
*/
As you can see, it's possible to call Foo()
both via an instance (a.Foo()
) or just via its enclosing class (A::Foo()
).
There are a couple of characteristics to keep in mind:
-
static
member functions don't havethis
pointer - A
static
member function can't be virtual -
static
member functions cannot access non-static
members - The
const
,const volatile
, andvolatile
declarations aren't available forstatic
member functions
As this
pointer always holds the memory address of the current object and to call a static member you don't need an object at all, it cannot have a this
pointer.
A virtual
member is something that doesn't relate directly to any class, only to an instance. A "virtual
function" is (by definition) a function that is dynamically linked, i.e. it's chosen at runtime depending on the dynamic type of a given object. Hence, as there is no object, there cannot be a virtual call.
Accessing a non-static
member requires that the object has been constructed but for static calls, we don't pass any instantiation of the class. It's not even guaranteed that any instance has been constructed.
Once again, the const
and the const volatile
keywords modify whether and how an object can be modified or not. As there is no object...
Probably we all got used to static
member functions already. Let's jump to the other usage of static
with functions.
Normally all functions declared within a cpp
file have external linkage by default, meaning that a function defined in one file can be used in another cpp
file by forward declaration.
As I recently learned, we can declare a free-function static
and it changes the type of linkage to internal, which means that the function can only be accessed from the given translation unit, from the same file where it was declared and from nowhere else.
With internal linkage, the linker can ignore the static
free-functions entirely bringing a couple of advantages:
- the free-function can be declared in a
cpp
file and we have a guarantee that it will not be used from any other place - speeds up the link-time as there is one less function to take care of
- we can put a function with the same name in each translation unit and they can be implemented differently. For example, you could create a logger that is implemented differently in each translation unit.
Today I shared with you what I learned recently from a code review that I was doing for someone else. I learnt that we can declare static
not only class member functions, but free-functions as well.
Having a class member function static means that it's part of the class, but there is no instance needed to call it, hence it cannot interact with members of the class.
Declaring a free-function static is about its visibility and the type of linkage. If you declare a free-function static, it will have an internal linkage and will not be accessible from any other file.
Have you ever used static free functions?
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