Disarium Number in Python

Disarium Number:

A Disarium number is one in which the sum of each digit raised to the power of its respective position equals the original number.

like 135 , 89 etc.

Example1:

Input:

number =135

Output:

135 is disarium number

Explanation:

Here 1^1 + 3^2 + 5^3 = 135 so it is disarium Number

Example2:

Input:

number =79

Output:

79 is not disarium number

Explanation:

Here 7^1 + 9^2 = 87 not equal to 79  so it is not disarium Number

Disarium Number in Python

Below are the ways to check Disarium number in python

• Using while loop
• By converting the number to string and Traversing the string to extract the digits

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Method #1: Using while loop

Algorithm:

• Scan the number and calculate the size of the number.
• Make a copy of the number so you can verify the outcome later.
• Make a result variable (with a value of 0) and an iterator ( set to the size of the number)
• Create a while loop to go digit by digit through the number.
• On each iteration, multiply the result by a digit raised to the power of the iterator value.
• On each traversal, increment the iterator.
• Compare the result value to a copy of the original number.

Below is the implementation:

# given number
num = 135
# intialize result to zero(ans)
ans = 0
# calculating the digits
digits = len(str(num))
# copy the number in another variable(duplicate)
dup_number = num
while (dup_number != 0):

    # getting the last digit
    remainder = dup_number % 10

    # multiply the result by a digit raised to the power of the iterator value.
    ans = ans + remainder**digits
    digits = digits - 1
    dup_number = dup_number//10
# It is disarium number if it is equal to original number
if(num == ans):
    print(num, "is disarium number")
else:
    print(num, "is not disarium number")

Output:

135 is disarium number

Method #2: By converting the number to string and Traversing the string to extract the digits

Algorithm:

• Initialize a variable say ans to 0
• Using a new variable, we must convert the given number to a string.
• Take a temp count =1 and increase the count after each iteration.
• Iterate through the string, convert each character to an integer, multiply the ans by a digit raised to the power of the count.
• If the ans is equal to given number then it is disarium number

Below is the implementation:

# given number
num = 135
# intialize result to zero(ans)
ans = 0
# make a temp count to 1
count = 1
# converting given number to string
numString = str(num)
# Traverse through the string
for char in numString:
    # Converting the character of string to integer
    # multiply the ans by a digit raised to the power of the iterator value.
    ans = ans+int(char)**count
    count = count+1
# It is disarium number if it is equal to original number
if(num == ans):
    print(num, "is disarium number")
else:
    print(num, "is not disarium number")

Output:

135 is disarium number